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authorPreston Pan <preston@nullring.xyz>2024-06-28 21:30:42 -0700
committerPreston Pan <preston@nullring.xyz>2024-06-28 21:30:42 -0700
commite7dd5245c35d2794f59bcf700a6a92009ec8c478 (patch)
tree0d0e81552f0426f8b715bd5bd3bdd0856058db2c /mindmap/inverse square.org
parent01ba01763b81a838dcbac4c08243804e068495b9 (diff)
stuff
Diffstat (limited to 'mindmap/inverse square.org')
-rw-r--r--mindmap/inverse square.org8
1 files changed, 7 insertions, 1 deletions
diff --git a/mindmap/inverse square.org b/mindmap/inverse square.org
index d55c24a..205c5f7 100644
--- a/mindmap/inverse square.org
+++ b/mindmap/inverse square.org
@@ -189,4 +189,10 @@ V(\vec{r}) := k\int_{space}\frac{\sigma(r')}{r}d\tau
\end{align*}
Note that because this field does not require keeping track of vector orientation, it is significantly easier to solve for \(V\) then convert to \(\vec{f}\). Additionally,
setting a reference point to something that is not infinity would be valid as well -- we just choose infinity because it cancels off the constant term. However,
-the /difference/ in potentials is absolute and does not require any constant adjustment.
+the /difference/ in potentials is absolute and does not require any constant adjustment. Then, the divergence of inverse
+square fields can be reformulated with the [[id:65004429-a6b7-41f2-8489-07605841da3d][Laplacian]] operator:
+\begin{align}
+\label{}
+\nabla^{2}V(\vec{r''}) = k\sigma(\vec{r''})
+\end{align}
+