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| author | Preston Pan <ret2pop@nullring.xyz> | 2026-04-11 13:14:04 -0700 |
|---|---|---|
| committer | Preston Pan <ret2pop@nullring.xyz> | 2026-04-11 13:14:04 -0700 |
| commit | 55e29f03ac3b537843f85892a1323e1f46321675 (patch) | |
| tree | e5796f03eaacb351fa8d8c612f852717ada4d2d6 /mindmap/function.org | |
| parent | f17203b32bd1ecb0d908bbf03b9239e2efde59d6 (diff) | |
new articles and snippets
Diffstat (limited to 'mindmap/function.org')
| -rw-r--r-- | mindmap/function.org | 15 |
1 files changed, 13 insertions, 2 deletions
diff --git a/mindmap/function.org b/mindmap/function.org index 5ed1efb..4343848 100644 --- a/mindmap/function.org +++ b/mindmap/function.org @@ -4,7 +4,6 @@ #+title: function #+author: Preston Pan #+description: Not the best explanation, but it functions. - #+options: broken-links:t * Definition @@ -17,6 +16,18 @@ S = \{(x, y): x^{2} = y, x, y \in \mathbb{R} \} \end{align*} Which is an example of a parabolic function. \(x\) and \(y\) can both conceptually be any object, but usually they are mathematical objects. Some examples of such objects include tensors and scalars. +** Surjectivity +:PROPERTIES: +:ID: de33062a-35cf-4eae-a6bb-38b76dd4faf3 +:ROAM_ALIASES: onto surjective +:END: +A function is /surjective/, or /onto/, if every element in the codomain is mapped onto by an element in the domain. +** Injectivity +:PROPERTIES: +:ID: c34ad97b-b536-40f2-91d1-cb2ce788628a +:ROAM_ALIASES: injective +:END: +A function is /injective/, or /one-to-one/, if every element in the domain maps to a unique element in the codomain. * ordered pair :PROPERTIES: :ID: 1b1b522e-d4de-4832-9ca4-c6d1cfee27e6 @@ -30,4 +41,4 @@ Where the element that is not explicitly a set gives us the definition of the fi * Function Group Let \((S, \circ)\) define a [[id:ba7b95b0-0ce6-4b33-9a79-5e5fddaea710][group]] where \(S\) is the set of all functions, and \(\circ\) is the composition binary operator. Then \(f(x) = x\) is the identity element, and an inverse of a function is defined -as \( (f \circ f^{-1})(x) = (f^{-1} \circ f)(x) = x \). +as \( (f \circ f^{-1})(x) = (f^{-1} \circ f)(x) = x \). This only works if all the functions in your group have inverses, obviously. |
